Math, asked by mrunmayeemm10, 1 month ago

solve the equation

x+2x-6=0


using the formula method.​

Answers

Answered by Felicx
1

Answer:

the roots of given quadratic equation are (√14 + √2)/2 , (√2 - √14)/2

Step-by-step explanation:

ax^2 + bx +c = 0

Then roots of above equation are

x=(-b + √(b^2 - 4ac))/(2a)

x= (-b - √(b^2 - 4ac))/(2a)

Compare given equation with general quadratic equation the we get following

2x^2 - 2√2 x-6 = 0

a=2

b=-2√2

c=-6

Roots are

x = {-(-2√2) + √((-2√2)^2 - 4(2)(-6))}/{2(2)}

x = (√14 + √2)/2

And

x = {-(-2√2) - √((-2√2)^2 - 4(2)(-6))}/{2(2)}

x = (√2 - √14)/2

Therefore the roots of given quadratic equation are (√14 + √2)/2 , (√2 - √14)/2

Answered by Anonymous
1

Answer:

Hope it helps!! Mark this answer as brainliest if u found it useful and follow me for quick and accurate answers...

Step-by-step explanation:

x^2+2x-6=0\\\\Here\:\:a=1,b=2,c=-6\\\\Then, x = \frac{-b\:±\sqrt{b^2-4ac}}{2a} \\\\\implies- \frac{(2)±\sqrt{(2)^2-4(1)(-6)} }{2(1)} \\\\\implies \frac{-2±\sqrt{28} }{2}\\\\\implies\frac{-2±2\sqrt{7} }{2}\\\\\implies  -1±\sqrt{7}

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