Question

Q.12) Fundamental period of tan3x is​

Answer 1

Answer:

period of the tangent function is π . Therefore, the period of tan(3x) is π3 ( 3x will increase by π units anytime x increases by π3 units). This means the period of y=2tan(3x) is π3 as well.

Answer 2

Answer:

The fundamental period of $tan3x$ is $\pi /3$.

Step-by-step explanation:

Given: $tan3x$

To find The fundamental period of tan3x.

Solution:

If the function $f(x)=tan(xs)$, where $s > 0$, then the graph of the function makes a complete cycle between $-\pi /2$  and  $\pi /2$ and the fundamental period of the function $f(x)$ is $\pi /s$

Let $f(x)=tan3x$

$xs=3x$

$s=3$

Hence, the fundamental period of $tan3x$ is $\pi /3$.