Question

Q.12. Give the formula of a compound in which carbon exhibit an oxidation state of A.+4 B. +2 C. -4​

Answer 1

Answer:

(A). CO2 , (B).CO (C).CH4

Explanation:

(A) In CO2 , Oxygen has oxidation no. of -4 ,so according to formula and let 'C' Oxidation no. be x.

X+(-4)=0

X=+4

(B)In CO , OXYGEN has oxidation no. of -2, so

X+(-2)=0

X=+2

(C) In CH4, HYDROGEN has oxidation no. of +4,so

X+4=0

X=-4