Question

Q.12 - If each side of a square is increased by 16%, find the percent
change in its area.
A-34.56%
B - 10.16%
C-24.46%
D - 44.58%​

Answer 1

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Let the side of an square be x

so,

the measurement of side after increasing 16%

= x +(16 %× x)

= x +[(16/100 )× x]

= x +( 4x / 25)

= (25x + 4x)/25= 29x/25

so,

the area when the side of the square be x = x²

and

the area when side increased 16%= (29x/25)²

= 841x²/625

so, the change in area=( 841x²/625) - x²

=( 841x²-625x²)/625

= 216x²/625

%of change in area

= [ (216 x²/625)÷841x²/625 ]×100

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