Q 12 While constructing an electrodynamometer type power factor meter, you have two rotating coils A and B having resistance R and inductance L respectively. You
adjusted the values of R and L to achieve a particular objective at normal frequency. What will be the effect of your action on the current through coil B at
frequency R= WL?
by nearly 450
Answers
Answer:
Gini Uni
Explanation:
he power factor meter measures the power factor of a transmission system. The power factor is the cosine of the angle between the voltage and current. The power factor meter determines the types of load using on the line, and it also calculates the losses occur on it.
No effect
Explanation:
A power factor metre circuit is made up of two coils: a pressure coil and a current coil in general. While the pressure coil is linked across the circuit, the current coil is attached in such a way that it can carry circuit current or a specific percentage of it. The electrical power factor can be computed on a properly calibrated scale by measuring the phase difference between the voltage and current. The pressure coil is usually divided into two parts: inductive and non-inductive, or pure resistive. There is no need for a controlling system because there are two opposing forces at equilibrium that balance the movement of the pointer without the need for a controlling force.