Question

Q.13 1F sin A=3/4 find cos A and
Tan A?*​

Answer 1

Answer :-

cos A = √7x/4x = √7/4..

tanA = 3x/√7x = 3/√7.

Step by step explanation :-

Given that sinA = ¾ .

So we know that sin∅ = perpendicular/hypontenuse .

So let the ratio be 3x:4x .

Let's find base.

=> base² = hypontenuse ² - perpendicular ²

=> base² = 4x² - 3x².

=> base² = 16x² - 9x².

=> base² = 7x²

=> base = √7x .

And we know that ,

• cos∅ = base / hypontenuse
• tan∅ = perpendicular/base.

So , here

• cos A = √7x/4x = √7/4.
• tanA = 3x/√7x = 3/√7.