Question

Q.13 A train accelerated from 10km/hr to 40km/hr in 2 minutes. How much distance does it cover in this period? Assume that the tracks are straight?
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Answer 1

welcome to the concept of kinematics

Time t=2 minutes  

Initial velocity = 10km/hr

Let us convert km/hr into m/s  

by multiplying 18/5

to the initial velocity.

intial speed

=10 × (18/5)

= 36 m/s  

Similarly, convert the  final velocity

Final velocity = 40 km/hr

= 136 m/s

we know v = u + at

from here

you get

a = 50 m/s ^2

then

$s = ut + \frac{1}{2} at {}^{2}$

then s = 172 m

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Answer 2

Answer:

Time t=2 minutes

Initial velocity = 10km/hr

Let us convert km/hr into m/s

by multiplying 18/5

to the initial velocity.

intial speed

=10 × (18/5)

= 36 m/s

Similarly, convert the final velocity

Final velocity = 40 km/hr

= 136 m/s

we know v = u + at

from here

you get

a = 50 m/s^2

then

s = ut + 1at² , S=172m

Step-by-step explanation:

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