Question

Q 13 i will mark as brainliest

Answer 1

Let the no of 50rs notes be x

20rs notes be y

10rs notes be z

50x+20y+10z=590

5x+2y+z=59......(1)

x/y=3/5

5x=3y........(2)

x+y+z=25

Multiplying by 5

5x+5y+5z=125

3y+5y+5z=125(from 2)

8y+5z=125.........(3)

Substituting value pf 5x in (1)

5y+z=59

Multiplying by 5

25y+5z=295........(4)

(4)-(3)

25y+5z-8y-5z=295-125

17y=170

[y=10]

5x=3y

x=30/5

[x=6]

5y+z=59

z=59-50

[z=9]

Therefore he had

6 50rs notes

10 20rs notes

9 10rs notes

It took me 10 mins to type all this u better mark me as brainliest....