Question

Q. 13. If the diagonals of a
parallelogram are x+y = 16 and
Y+7= 20 then value of x and y
are​

Answer 1

✬ x = 3 ✬

✬ y = 13 ✬

Step-by-step explanation:

Given:

• Diagonals of parallelogram are x + y = 16 and y + 7 = 20

To Find:

• What is the value of x and y ?

Solution: Let ABCD be a parallelogram where

• AC and BD = Diagonals

Let the both diagonal bisect each other point O such that AO = OC & DO = OB

• AO = 16
• OC = x + y
• DO = 20
• OB = y + 7

➟ DO = OB

➟ 20 = y + 7

➟ 20 – 7 = y

➟ 13 = y....(1)

And also

➟ AO = OC

➟ 16 = x + y

➟ 16 = x + 13 (from equation 1)

➟ 16 – 13 = x

➟ 3 = x

Hence, the values of x and y is 3 and 13 respectively.

_______________

★ Verification ★

➭ x + y = 16

➭ 3 + 13 = 16

➭ 16 = 16

➭ y + 7 = 20

➭ 13 + 7 = 20

➭ 20 = 20

Answer 2

✒ Given :-

• Diagonals of a Parallelogram :- x+y = 16 and y+7 = 20.

✒ To Find :-

• The Value Of X and Y.

✒ Solution :-

⭐ Let,

The Equation x+y = 16 be Equation 1.

The Equation y+7 = 20 be Equation 2.

Now,

First, Take The Equation 2 :-

➠ y+7 = 20.

Use Transposition.

➠ y = 20-7

Subtract them.

➠ y = 13.

So, The Value Of Y = 13.

Now,

Put the value of Y in Equation 1 :-

➠ x+y = 16.

➠ x+13 = 16.

Use Transposition.

➠ x = 16-13

Subtract them.

➠ x = 3.

So, The Values Of X and Y are 3 and 13 respectively.