Question

Q.13 If the zeroes of the polynomial x2-3x²+x+1 are a-b, a, a+b.
Find a and b.​

Answer 1

Step-by-step explanation:

Sum of zeroes=(-b/a)

(a-b)+(a)+(a+b)=(3/1)

3a=3

a=1

product of zeroes=(-d/a)

(a-b)(a)(a+d)=(-1/1)

(a^2-b^2)(a)=(-1)

a^3-ab^2=(-1)

(1)^2-(1)b^2=(-1)

1-b^2=-1

b^2=2

b=(+√2 and -√2)