Q.13 Two opposite angles of a
parallelogram are (5x – 20)° and (70 -4x)" , so one of the angles of a parallelogram is...
O a) 50°
Ob) 80°
c) 30°
O d) 140
Answers
Step-by-step explanation:
Assuming 2nd angle as (5x-20)° instead of (5x-20)'', considering it to be a typo error.
From properties of a parallelogram we know that Opposite angles of a parallelogram are equal.
Here, it is mentioned that the given angles are opposite.
So ,on equating, we get :
5x-20=70-4x
5x+4x=70+20 (on moving variables on one side and constant on one side)
9x=90
we get,
x=10.
Now, 5x-20 becomes 5*10-20=50-20=30
So correct answer is 30°
Answer:
Given :-
Two opposite angles of a parallelogram are (5x – 20)° and (70 -4x).
To find :- Angles of parallelogram.
Solution :-
Let ABCD be a parallelogram.
/_A = /_B = ( 5x - 20)° ......(Given)
/_C = /_D = (70° - 4x)° .......(Given)
Therefore,
/_A = /_C
(5x - 20)° = (70 - 4x)°
........(Opposite angles of parallelogram)
5x + 4x = 70 + 20
9x = 90°
x = 10°
/_A = /_B = 5x - 20° = 50° - 20° = 30°.
/_C = /_D = (70° - 4x) = 70° - 40° = 30°
Answer :- C) 30°.
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