Question

Q.14 The sum of three consecutive multiples of 9 is 324. Find these multiples.


{please explain also}​

Answer 1

Question:-

• The sum of three consecutive multiples of 9 is 324. Find these multiples.

To find:-

• The three consecutive multiples of 9

Solution:-

• Let the consecutive multiples be x , x+1 and x+2

• We are given that the sum of multiples is 324

• As they are the multiples of 9 the equation formed will be:-

$\\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \red \leadsto \: { {\boxed{ \bf \: 9 \times x + 9(x + 1) + 9(x + 2) = 324}}}$

$\\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \pink \leadsto \bf \: \: 9x + 9x + 9 + 9x + 18 = 324$

$\\ \: \: \: \: \: \: \: \: \: \orange \leadsto \bf \: \: 27x + 27 = 324$

$\\ \: \: \: \: \: \: \: \: \green \leadsto \bf \: 27x = 324 -27$

$\\ \: \: \: \: \: \: \: \: \blue \leadsto \bf \: 27x = 297$

$\\ \: \: \: \: \: \: \: \: {\color{navy}{ \leadsto }} \: \bf \: 27x = 297$

$\\ \: \: \: \: \: \: \: \: { \color{brown}{\leadsto}} \: \bf \: x = \frac{297}{27}$

$\\ \: \: \: \: \: \: \: \: { \color{yellow}{\leadsto}} \: \bf \: x = 11$

• Therefore the required value for x is 11.

Now the multiples would be

• 11
• x+1= 11+1=12
• x+2 =11+2=13

The multiples are 11,12,13

━━━━━━━━━━━━━━━━━━━━━━━━

${ \huge{ \underline{ \underline{ \boxed{ \mathfrak{ \color{goldenrod}{Verification : - }}}}}}}$

$\\ \: \: \: \: \: \: \: \: \mapsto \: (9 \times 11) +( 9 \times 12) + (9 + 13)$

$\\ \: \: \: \: \: \: \: \: \: \: \: \mapsto \: 99 + 108 + 117$

$\\ \: \: \: \: \: \: \: \: \: \mapsto \: 324$

$\large{ \boxed{ \mathfrak{ \pink{Hence \: verified }}}}$

$\color{goldenrod}{━━━━━━━━━━━━━━━━━━━━━━━━━━━━━}$

Answer 2

Answer:

thank u for points

thank u again