Q. 16. A body thrown up vertically reaches a maximum
height of 100 m. Another body with double the mass thrown up
with double the initial velocity reaches a maximum height h. What
is the value of h?
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Answer:400m
Explanation:let initial velocity = v
H=V^2/2g
100=v^2/20. (g=10 m/s)
V=√2000
Now
v' = 2v
Thus ,
H' =v'^2/2g =4v^2/20
=8000/20
=400
Answered by
0
Answer:
100 is answer
I think this is correct
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