Question

Q.16. In right angle ∆ABC, AB = x cm, BC = (x + 1) cm, CA = (x + 2) cm, then area of
∆ABC equal to ?​

Answer 1

Answer:

$area = \: \frac{1}{2} \times base \times height \\ = \frac{1}{2} (x + 1)x \\ = \frac{ {x}^{2} + x}{2} \: {cm}^{2}$