Question

Q.17
In an isosceles A ABC, AB=5 cm AC=5 cm and half triangle ABC =70° ,half triangle BAC =​

Answer 1

Answer:

AB=AC=5 cm

then

angle ABC= angle ACB= 70°

ABC + ACB + BAC = 180°

BAC= 180°-(70°+70°)

BAC=180°-140°

BAC=40°