Math, asked by dafyash214, 8 months ago

Q.18) A box contain 5 green pencils and 7 yellow pencils. Two pencils are
chosen at random from the box without replacement. what is the probability
that both are yellow?​

Answers

Answered by nanuaro
0

Answer:

Plz Mark as brainlist

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Answered by nilesh102
4

hi mate

here you want to find the probability of two events happening, we must multiply the probability of each separate event happening by the other.

So,mate for the first time that you pick a pencil, we have to find the probability that it is a yellow pencil. 

Probability = favorable outcomes / total possible outcomes = 7 yellow / 7 yellow + 5 green = 7 yellow pencils / 12 total pencils

Thus, the probability of the first event is 7/12.

According to the question, we want to pick a yellow pencil both times, but we don't replace it.  So, assuming we pick a yellow pencil, we have to subtract that from the next calculation.

Thus, probability of the second event = probable outcomes/ total outcomes = 6 yellow pencils / 6 yellow + 5 green pencils = 6 / 11

Therefore, the second event's probability is 6/11.

To find the total probability, we must multiply the two fractions together.

7 / 12 * 6 / 11 = 42 / 132

But, we want to simplify this fraction, so:

42 / 132 = 42 ÷ 6 / 132 ÷ 6 = 7/22

Thus, the probability is 7/22, or approximately 32%.

OR. mate you want to find that by total no of pencils n(S)=5+7=12

let E be the event of getting different colour

So n(E) =2

therefore P(E)=n (s)/n (E)

=2/12

=1/6

i hope mate it helpfull to you...

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