Question

Q.19) A body starting from rest has an
acceleration of 20ms Calculate,
(a.) distance travelled by body in 8sec.
b.) Velocity after travelling a distance
10m.(c.) distance travelled by it in 5th second​

Answer 1

Answer:

a) 640m

b)20m/s

c)250m

Explanation:

a)s=ut+1/2at^2

s=0×8+1/2×20×8×8

s=640m

b)v^2-u^2=2as

v^2-0^2=2as

v^2=2as

v^2=2×20×10

v=√400

v=20m/s

c)again

s=ut+1/2at^2

s=0×5+1/2×20×5×5

s=250m

Answer 2

Explanation:

The upper one is correct but

there is one mistake in the last answer c

we have to use the formula

S nth = u + a/2 (2n-1)

= 0+ 20/2 ( 2(5)-1)

= 10×9

= 90m