Question

Q.19 Find the sum of the first 10 multiples of 6​

Answer 1

Answer:

the first multiple of 6 are 6, 12, 18, 24 ,30 ,36

n= 10

a =t1 = 6

tn = 361

now

Sn = n/2 [ t1 + tn ]

=10/2 [ 6+36]

=5 [42]

=210

the sum of 1st 10 no. multiple of 6 are 210

Step-by-step explanation:

Answer 2

Step-by-step explanation:

6+12+18+24+30+36+42+48+54+60

now sum all these numbers

so,the sum of these numbers is 330