Q. 2: A bag contains a red ball, a blue ball and a yellow ball, all the balls being of the same size. Kritika takes out a ball from the bag without looking into it. What is the probability that she takes out the
(i) yellow ball?
(ii) red ball?
(iii) blue ball?
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Answer:
in the bag every ball is one in number so the probability will be 1 for every ball.
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Kritika takes out a ball from the bag without looking into it. So, it is equally likely that she takes out any one of them from the bag.
Let Y be the event ‘the ball taken out is yellow’, B be the event ‘the ball taken out is blue’, and R be the event ‘the ball taken out is red’.
The number of possible outcomes = Number of balls in the bag = n(S) = 3.
(i) The number of outcomes favourable to the event Y = n(Y) = 1.
So, P(Y) = n(Y)/n(S) =1/3
Similarly, (ii) P(R) = 1/3
and (iii) P(B) = ⅓
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