Question

Q. 2 B] complete the following activities. Which number should be added to 12. 16 and 21 so that the resultant numbers are 1) in continued proportion? Solution : Let the number x be added to each of the given numbers. Then the numbers and are in continued proportion. k (Say) 16 + x 21 + x 4 k = 12 - -/- 16 +1 -21 - -- (16 +x) - (21 - x) 5 12 + 4 x 12+x=4x + x) = 4 - 5​

Answer 1

Answer:

THE VALUE MUST SUBSTITUTED FROM THE NUMBERS IS 4

Step-by-step explanation:

GIVEN NUM ARE IN PROPORTIONAL

12,16,21

FORMULA A:B=B:C

EACH NUM CAN ADD A NUM IT CAN BE IN CONTINUED PROPORTIONAL

THE NUMBERS ARE (12+X) : (16+X) = (16+X) : (21 : X)

(12 + X) / (16 + X) = (16+X) / (21+X)

(12 + X) (21 + X) = (16 + X) (16 + X)

252 + 12x + 21x + x² = 256 + 16x + 16x + x²

256 - 252 + 32x - 33x = 0

4 - x = 0

$x = 4$

THE VALUE MUST SUBSTITUTED FROM THE NUMBERS IS 4