Q.2.B) Solve the following questions( 2 mark each)
1. If(a + b + c)(a -b + c) = a²+ b² + c² hen show that a,b,c are in
continued proportion.
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if elements are in gp then those elements are in continuous proportion
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Solution :
(a + b + c)( a - b + c ) = a² + b² + c²
→ a ( a - b + c ) + b ( a - b + c ) + c ( a - b + c ) = a² + b² + c² .
→ a² - ab + ac + ab - b² + bc + ca - bc + c² = a² + b² + c²
→ a² - b² + c² + 2ac = a² + b² + c²
→ 2b² = 2ac
→ b² = ac
→ b × b = a × c
→ b / a = c / b .
→ a : b :: b : c .
Hence , a , b , and c are in continued proportion .
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