Question

Q.2: Does the polynomial a4 + 4a2 + 5 have real zeroes?

Answer 1

Answer:

Here is your answer friend :)

Step-by-step explanation:

In the aforementioned polynomial, let a2 = x.  

Now, the polynomial becomes,  

x2 + 4x + 5  

Comparing with ax2 + bx + c,  

Here, b2 – 4ac = 42 – 4(1)(5) = 16 – 20 = -4  

So, D = b2 – 4ac < 0  

As the discriminant (D) is negative, the given polynomial does not have real roots or zeroes.