Question

Q#2. One third of the sum of two angles is 60 and one quarter of their difference is 28.Find the two angles.

Answer 1

Answer:

$\frac{1}{3} (x +y) = 60$

$x+y = 180$  -------- 1

$\frac{1}{4} (x-y) = 28$

$x-y = 112$ ______ 2

Adding 1 and 2 with elimination method

x + y + x - y = 180 + 112

2x = 292

x = 146

substituting x in 1

x + y = 180

146 + y = 180

y = 180 - 146

y = 34

Answer 2

1/3 (x+y)=60=)x+y=180

1/4 (x-y)=28=)x+y=112

x+y=180

x-y=112 so after adding both we get x=146 and y=34

Hope it will help you.