Question

Q. 2 : Pravin has applied a force of 100 N on an object, at an angle of 600 to the horizontal. The object gets displaced in the horizontal direction and 400 J work is done. What is the displacement of the object?

Answer 1

Answer:

Given,

Mass=40kg,

v=1m/s

,v=2m/s

According to the work-energy conversion theorem;

Work done by the force= Change in Kinetic energy,

Work done by the force =(  2 1 )×m×(v  2 −u  2)

Work done =0.5×40×(4−1)=60J

Answer 2

Answer:

The object will be displaced through 8 m.

Explanation:

The object will be displaced through 8 m.

Explanation:

GIVEN:

∅ = 60°

F = 100 N

W = 400 J , s = ?

W = F s Cos ∅

$400 = 100 \times s \times \frac{1}{2}$

$\frac{400}{100} = \: \frac{1}{2} \times s$

$4 \times 2 = s$

.

. .

$s = 8m$

The object will be displaced through 8 m.