Question

Q. [2] Solve it

1. If a=4, b=2 .Find the value of 5a-2b /4b-8 .

2. Write the following using numbers, literals and signs of arithmetic operators.

a. sum of x and y subtracted from ½.

b. From the sum of 14 and x,subtract 3 times y.

c. Twice x increased by 17​

Answer 1

Answer:

1 ans=0

5*4-2*2/4*2-8=0

2.

a)ans=x+y-1/2=2x+2y-1

b)ans=x-3y+14

c)ans=x+17

Answer 2

Answer:

$1) \: \: \: \frac{5a - 2b}{4b - 8} \\ \frac{5(4) - 2(2)}{4(2) - 8} \\ = \frac{20 - 4}{8 - 8} \\ = \frac{16}{0} \\ = \underline{ \underline{0}} \\ \\ 2) \\ a) \: \: \: \frac{1}{2} - (x + y) \\ b) \: \: \: (14 + x) - 3y \\ c) \: \: \: 2x + 17$