Q. 2. Velocity time graph of a car is shown below. Answers the following question:
What is the total distance travelled by the car ?
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Answer:
when object moving along straight line covers equal distances in equal intervals of time, it is said to be in uniform motion along a straight line.
distance traveled by Car =
difference between distance traveled by scooter and car after 15 sec = 112.5m
total at
car catch up with scooter then 30t = 337.5+45(t-15)
or 30t = 337.5+45t-675
or 15t = 337.5
t = 22.5sec
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Explanation:
Total diatance covered by the car is area of trapezium OABC.
AB = 30 - 10 = 20
OC = 40
height = 20
Area = 1/2 × 20 × (40 + 20) = 10 × 60 = 600
So, distance covered = 600 m.
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