Question

(Q. 20)find d^2y/dx^2, if y= logx

answer this plz​

Answer 1

Answer:

- 1 / x²

Step-by-step explanation:

Given :

y = ㏑ x

Diff. w.r.t. x :

d y / d x = 1 / x

Again w.r.t. x :

= > d² y / d x² = ( x⁻¹ )'

= >  d² y / d x² = - 1 . ( x⁻¹⁻¹ )

= >  d² y / d x² = - x⁻²

= >  d² y / d x² = - 1 / x²

Hence we get required answer!