Question

Q.20) Jay, Babita, Keshav and Deepa are standing on 4 (different) corners of square. Jay moves towards Keshav
and reaches at his position in 2012 steps. Now Keshav will reach on Deepa's position in
A) 4 steps
B) 20 steps
C) 10V2 steps
D) Insufficient data
O
T​

Answer 1

Given :  Jay, Babita, Keshav and Deepa are standing on 4 (different) corners of square. Jay  moves towards Keshav and reaches at his position in 20√2 steps  

To Find : Keshav will reach on  Deepa's position in​ how many steps

Solution:

Let say this  is square with 4 vertex

Jay  , Babita , Keshav & deepa

Sides are :

Jay - Babita

Babita - Keshav

Keshav - deepa

deepa - Jay

Diagonals are

Jai - keshav    

Babita - deepa

Diagonal  = Side√2   in square

Jay  moves towards Keshav and reaches at his position in 20√2 steps

Diagonal   = 20√2

=> Side√2 = 20√2

=> side = 20 steps

Keshav - deepa is side

Hence Keshav will reach on  Deepa's position in​ 20 steps

option B is correct

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Answer 2

Answer:

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