Question

Q-21. An elevator descends
into a mine shaft at the rate of
5 m/min. If the descent starts
from 50 m above the ground
level, how long will it take to
reach - 350 m.​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

AnswEr :

• Elevator will take 80 min or 1 hour 20 min .

ExplanaTion :

We are given that an elevator descents into a mine shaft at the rate of 5 m/min . Also, it is given that descent starts from 50 m above the ground level .

Here, we are supposed to find the time taken by elevator to reach the distance of -350 m [ Below the ground level ] .

Accordingly, we'll find the total distance elevator has to travel and time taken by it.

So,

Total distance elevator is supposed to travel = Initial position of the elevator - final position of the elevator.

⇛ 50 - ( - 350 )

⇛ 350 + 50

⇛ 400 m

We are given the rate at which elevator descents, which is 5 m/min .

which implies,

• Elevator travels 5 m in 1 min

• Elevator travels 1 m in 1/5 min

So,

Time taken by elevator to travel the distance of 400 m :

➟ 1/5 × 400

➟ 80 min.

➟ 1 hour 20 min.

Therefore, Elevator will take 80 min or 1 hour 20 min .