Question

Q.22. A rectangle is (8x + 5)cm long and 3 points
(5x + 3)cm broad. Find its area. *
O
(40x + 50x + 15) sq.cm.
O (40x2 + 49% +15) sq.cm.
O )
(50x + 59x + 15) sq.cm.
O (50x2 + 50x + 15) sq.cm.​

Answer 1

QUESTION:

Length of rectangle is (8x+5) and its breadth is (5x+3).Find its area.

ANSWER:

$\sf☆Area \: of \: rectangle \: =length×breadth$

$\large \sf : \implies(8x + 5) \times (5x + 3)$

$\large \sf : \implies8x (5x + 3) + 5(5x + 3)$

$\large \sf : \implies \: 40 {x}^{2} + 24x + 25x + 15$

$\large \sf : \implies \: 40 {x}^{2} + 49x + 15$

So area of rectangle is 40x²+49x+15 cm²

MORE FORMULAE TO KNOW!!

• Area of square=side²
• Perimeter of rectangle=2(L+B)
• Perimeter of square=4×side
• Area of triangle=½×base×height

Answer 2

☆ Length of rectangle = (8x + 5) cm

☆ Breadth of rectangle = (5x + 3)cm

Perimeter of rectangle = l × b

--> (8x + 5) × (5x + 3 )

--> 40x^2 + 24x + 25x + 15

--> 40x^2 + 49x + 15

I hope it helps u dear friend ^_^♡♡