Q.23 Draw a number line and answer the following:
(a) Which number will we reach if we move 4 numbers to the right
of - 2.
(b) Which number will we reach if we move 5 numbers to the left of
1.
(C) If we are at - 8 on the number line, in which direction should we
move to reach - 13?
(d) If we are at - 6 on the number line, in which direction should we
move to reach - 1?
Answers
Step-by-step explanation:
Let the angle formed by the triangle at Canton = C
And the angle formed by the triangle at Naples = 90 - 44 = 46°
sin (46 ) / 680 = sin C / 545
545 * sin ( 46 ) / 680 = sin C
arcsin ( 545 * sin (56) / 680 ) = C ≈ 35.2°
Draw a perpendicular from Elgin to the base of the triangle...call the point of intersection with the base, P
So let the triangle formed by P , C and the angle formed by the perpendicular at Elgin be PCE
So angle CEP = 90 - = 54.8°
This angle is supplemental to 180
The suplemental angle is 125.2°
In terms of bearing, the bearing from Elgin to Canton = 360 - 125.2 = 234.8° ≈ 235°
CORRECTED !!!!
Step-by-step explanation:
(i) ∠COB = 2 ∠CAB = 2x° (angle at the centre = 2 × angle at the remaining part of the circumference) (ii) ∠OCD = ∠COB = 2x° (alternate ∠s, DC || AB) OD = OC (radii of the same circle) ⇒ ∠OCD = ∠ODC ⇒ ∠ODC = 2x° ∴ In ∆DOC, ∠DOC = 180° – (2x° + 2x°) = 180° – 4x° (∠sum prop. of a ∆) (iii) ∠DAC = 1212∠DOC = 1212 (180 − 4x)° (angle made by arc DC at the centre = Twice the angle at the remaining part of the circumference) = (90 – 2x)° (iv) In ∆ADC, ∠ACD = ∠CAB = x° (alt ∠s; DC || AB) ∴ ∠ADC = 180° – (x° + 90° – 2x°) = (90 + x)°. (∠sum prop. of a ∆)Read more on Sarthaks.com - https://www.sarthaks.com/976954/the-figure-given-diameter-of-the-circle-with-centre-and-cd-ba-if-cab-find-the-value-cob-doc