Question

Q 23 If in a certain code language, "ACQUIT" is coded as "ZERWHV", then how would "SMOOTH" be coded in the san
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Answer 1

Answer:

ROPQVJ

Step-by-step explanation:

Z is previous of A so S previous alphabet is R

E is 2nd alphabet after C so after M ,2nd term is O and so on.

Answer 2

The coded form of "SMOOTH" would be "HNLLGS".

To decipher the code for "SMOOTH", we need to understand the pattern used in the coding of "ACQUIT" to transform each letter into its corresponding code.

One possible approach is to consider the position of each letter in the English alphabet, and the position of its code letter in the reverse order of the alphabet. For example, the first letter "A" is the 1st letter of the alphabet, and its code letter "Z" is the 26th letter of the reverse alphabet. So there is a difference of 25 positions between them.

Using this pattern, we can apply the same transformation to each letter in "SMOOTH":

• S -> H (position difference: 18)
• M -> N (position difference: 13)
• O -> L (position difference: 10)
• O -> L (position difference: 10)
• T -> G (position difference: 7)
• H -> S (position difference: 8)

for such more question on coded language

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