Question

Q
23.
The height at which the value of acceleration due to gravity becomes 50% of that at the
surface of the earth. (Radius of the earth = 6400 km) is​

Answer 1

Answer:

The new value of gravity at a height h is given as g′=

(R+h)

2

gR

2

As visible from the formula that incresing h results in decresing gravity.

So just put g′=g/2 i.e. 50% less than g where g is gravity at surface. so we get g/2=

(R+h)

2

gR

2

or

2

1

=

(R+h)

2

R

2

or

1

2

=

R

2

(R+h)

2

or

2

2

=

R

R+h

=1+h/R putting values we get

R

h

=1.414−1=0.414

so h=0.414R=2649.6Km

Option C is correct.

Explanation:

answer is 2650