Question

Q.24. A train travelling at a speed of 90Km/hr, breaks are applied so as to produce a uniform
acceleration of -0.5m/s. Find how far will the rain go before it is brought to rest​

Answer 1

Solution :-

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=> U = 90 km/h => 25 m/s

=> V = 0

=> A = -0.5 m/s^2

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Using Third Equation

=> V^2 - U^2= 2AS

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=> (0)^2 - (25)^2 = 2(-0.5)(S)

=> -625 = -S

=> S = 625 meters

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