Q.26 Prove" The sum of the angles of a triangle is 180°.
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Theorem : Angel sum property of triangle.
Statement : The sum of the angles of a triangle is 180°
Given : ABC is a triangle with angle ∠B , ∠A
To prove : ∠A+ ∠B + ∠C = 180°
Construction: Though A draw a line PQ||BC
Proof : PQ||BC (by construction)
and AB is transversal
∠1 = ∠B (Alternate interior angle) ------- 1
similarly AC is a transversal and PQ||BC
=> ∠2+ ∠c (alternate interior angle)--------2
PAQ is straight line
∠1 + ∠2 + ∠3 = 180°
∠B+ ∠A + ∠C = 180° (from 1 & 2)
∠A + ∠B + ∠C = 180°
Hence , the sum of the angles of a triangle is 180° .
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