Question

Q.28
The potential energy of a projectile at maximum
height is 3/4 times kinetic energy of projection.
Its angle of projection is
(1) 30°
(2) 45°
(3) 60°
(4) none​

Answer 1

Answer: Let the angle of projection be ¢ and projection velocity be u.

The at max. height

U = (Ki*3)/4

Here, ki is initial kinetic energy.

Max height is [u^2sin^¢]/2g

=> [mg*u^2sin^2¢]/2g = [3mu^2]/8

=> sin^2¢ = 3/4

=> sin¢ =√3/2

=> ¢ = 60°

So, the angle of projection is 60°.

Answer 2

Answer:

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