Question

q 29 please answer as quick as possible
only answer if u know​

Answer 1

area of eq triangle=√3a²/4

where a=lenght of one side

height of eq triangle=√3a/2

ar=1cm²

1=√3a²/4

a²=4/√3

as triangle ABC has height equal to 4a  (approx)

and base equal to 3h

area=1/2*base*height

=1/2*3h*4a

=1/2*3*√3/2*4*a²

=3√3*4/√3

=12

but we have taken height to be 4a whereas its 3.7a

so our answer should be just less than 12 ie 11 =option A

though i m not very confident about A but it can also be B