Q.3-A squirrel is running along a fence. Mr. Jensen, curious about squirrel velocities, has shrewdly observed at which fence post the squirrel is located at one-second intervals. After the squirrel has run away, Mr. Jensen measures the spacing between two adjacent fence posts to be 5 m.
Time: 0.0 sec 1.0 sec 2.0 sec 3.0 sec 4.0 sec 5.0 sec 6.0 sec
Distance: 0.0 m 5.0 m 15 m 25 m 35 m 55 60
Question 1:
Based on his observations, Mr. Jensen estimates the squirrel’s velocity between measurements.
Question 2:
By taking the average of the above velocities, calculate the squirrel’s average velocity over he entire 6 seconds.
Answers
Given : squirrel is running along a fence. Mr. Jensen, curious about squirrel velocities, has shrewdly observed at which fence post the squirrel is located at one-second intervals.
To Find : squirrel’s velocity between measurements.
By taking the average of the above velocities, calculate the squirrel’s average velocity over he entire 6 seconds.
Solution:
Time Distance Velocity
0 0
1 5 ( 5 - 0)/( 1- 0) = 5 m/s
2 15 ( 15 - 5)/( 2- 1) = 10 m/s
3 25 ( 25 - 15)/( 3- 2) =10 m/s
4 35 ( 35 - 25)/( 4 - 3) = 10 m/s
5 55 ( 55 -35)/( 5- 4) = 20 m/s
6 60 ( 60 - 55)/( 6- 5) = 5 m/s
Average of velocities = ( 5 + 10 + 10 + 10 + 20 + 5 ) / 6
= 60/6
= 10 m/s
This average can be calculated only when time interval are same as the case is here
Total Distance = 60 m Total time = 6 sec
Average velocity = 10 m/s
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