Q.3 A student dissolves 100 gm of sugar in 50 ml of water in a beaker A. He dissolve 10 gm of sugar in 50 ml of water. He then put few raisins of equal weight in both beakers. What will happen to the raisins in
beaker A and B after few hours? Explain properly
Answers
Answered by
0
Answer:
2
Explanation:
100/50 = 2
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Answered by
1
Answer:
sugar concentration of raisins is lower than that of solution A and higher than that of solution B.
sugar concentration of raisins is higher than that of solution A and lower than that of solution B.
in B the cell membrane of raisins was damaged resulting in bleaching
in A the permeability of water of the cell membrane of raisins was enhanced
Answer :
B
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