Q-3 (b) may i know the answer of my question
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cos11°+sin11°
=cos(90°-79°)+sin11° [∵, cos(90°-Ф)=sinФ]
=sin79°+sin11°
=2sin(79°+11°)/2cos(79°-11°)/2 [∵, sinC+sinD=2sin(C+D)/2cos(C-D)/2]
=2sin45°cos34°
=2×1/√2×cos(90°-56°)
=√2sin56° (Proved)
=cos(90°-79°)+sin11° [∵, cos(90°-Ф)=sinФ]
=sin79°+sin11°
=2sin(79°+11°)/2cos(79°-11°)/2 [∵, sinC+sinD=2sin(C+D)/2cos(C-D)/2]
=2sin45°cos34°
=2×1/√2×cos(90°-56°)
=√2sin56° (Proved)
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