Question

Q.3} Find the value of a and b for which (2a-1)x+3y-5=0 ; 3x+(b-1)y-2=0 have infinite many solutions​

Answer 1

Answer:

11/5

Step-by-step explanation:

(2a-1)x+3y-5=0

3x+(b-1)y-2=0

If a system of linear equations has infinite number of solutions then the condition is a₁/a₂=b₁/b₂=c₁/c₂

(2a-1)/3=3/(b-1)=5/2

2a-1/3=5/2

4a-2=15

a=17/4

3/b-1=5/2

6=5b-5

11=5b

b=11/5

Answer 2

Answer:

Step-by-step explanation:

2A-1/3=3/B-1=5/2

4A-2=15

A=17/4

5B-5=6

5B=11

B=11/5