Question

Q.3 If P(Y)= 4+3y-Y

2+5y3

, Find P(3)​

Answer 1

Step-by-step explanation:

p(y)=4+3y-y²+5y³

     =5y³-y²+3y+4

p(0)=5y³-y²+3y+4

     =5*(0)³-(0)²+3*0+4

     =5*0-0*3+0+4

     =0-0+0+4

     =4

p(1)=5y³-y²+3y+4

    =5*(1)³-(1)²+3*1+4

    =5*1-1+3+4

    =5-1+7

    =4+7

    =11

p(2)=5y³-y²+3y+4

     =5*(2)³-(2)²+3*2+4

     =5*8-4+6+4

     =40-4+10

     =36+10

     =46

so, p(0)=4 , p(1)=11 , p(2)=46

Answer 2

Answer:

p(y)=4+3y-y²+5y³

p(3)=4+3(3)-(3)²+5(3)

=4+9-9+5(27)

=4+135

p(3)=139