Q.3) The distance of the point P(-6, 8
) from the origin is:
8
10
257
6द डिस्टेंस ऑफ द पॉइंट ब्रैकेट - 6 - 8 पैकेट लॉस फ्रॉम द ओरिजिन
Answers
Answered by
1
Answer:
10
Step-by-step explanation:
√x²+y²
=√(-6)²+8²
=√100 =10
Answered by
1
Step-by-step explanation:
Distance formula
d=√((x2-x1)²+(y2-y1)²)
put x1=0 y1=0 as origin
x2=-6 ' y2=8
d=√ (-6-0)²+ (8-0)²
= √(36 + 64)
= √ 100
= 10 units
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