Question

Q.3=verify by substitution that ?I(I) the root of 3x-5=7 is x=4

Answer 1

Answer:

heya mate ☺

$given \: x = 4 \\ 3x - 5 = 7 \\ putting \: back \: the \: value \: of \: x \\ = > 3(4) - 5 = 7 \\ = > 12 - 5 = 7 \\ = > 7 - 7 = 0 \\ = > 0 = 0$

So LHS = RHS = 0

✔ hope it helps u ✔