Question

Q.31.In ∆ABC AB=AC and AD is the
median drawn on BC, then ∆ABD
=∆ACD by which criterion ?​

Answer 1

Answer:

∆ABD=∆ACD

Step-by-step explanation:

AB=AC (given) {1}

AD is the median drawn on BC,

therefore, BD=CD {2}

AD=AD (same side) {3}

Hence from 1,2&3

∆ABD=∆ACD

Answer 2

Answer-SAS

Step-by-step explanation:

AB=AC. (given)

so angleA = angleB. (property of isoceles ∆)

AD=DA. (common)

so by SAS ∆ABD congruents to ∆ACD