Question

Q.4 An iron rod is placed parallel to magnetic field
of intensity 2000 A/m. The magnetic flux
through the rod is 6 x 10-4 Wb and its cross
sectional area is 3cm2 Calculate the
magnetic permeability of the rod in Wb/m​

Answer 1

Answer:

Correct option is

C

10

−3

Cross-sectional area A=3×10

−4

m

2

Magnetic flux through the rod ϕ=6×10

−4

Wb

Magnetic field intensity H=2000 A/m

Using ϕ=BA and B=μH

We get magnetic permeability μ=

AH

ϕ

∴ μ=

3×10

−4

×2000

6000

=10

−3

A−m

Wb