Question

Q.4) Calculate the no. of moles (n) and molecules present in 3.2x10
mg of methane (C=12, H=1).
51 What is hydrogen honding? Show hydrogen bonding in wtor molecular​

Answer 1

Methane formula ⇒CH4

molar mass of methane ⇒16g

given mass of methane = 3.2×10 mg = 32 × 10^-3g

moles = (32×10^-3)/16

       =0.002moles

1 moles = 6.022×10^23 molecules

therefore 2×10^-3 (0.002) moles⇒  0.002×6.022×10^23

                                                     =12.044×10^20 molecules

HYDROGEN BONDING :Hydrogen bonding is a special type of dipole-dipole attraction between molecules, not a covalent bond to a hydrogen atom. It results from the attractive force between a hydrogen atom covalently bonded to a very electronegative atom such as a N, O, or F atom and another very electronegative atom. Hydrogen bond strengths range from 4 kJ to 50 kJ per mole of hydrogen bonds.