Question

Q.4 Calculate the Number of
protons present in 11.2 mL
of Steam at 273K and I atm
pressure.​

Answer 1

Answer:

30.1 * 10^19 = no. of protons in 11.2 ml

Explanation:

1 mole = 22.4 L

1/22.4  = 1 L

1/22.4 * 0.0112 = 11.2 ml

0.0005 moles = 11.2 ml

0.0005 * 6.02 * 10^23 = no. of protons in 11.2 ml

30.1 * 10^19 = no. of protons in 11.2 ml