Question

Q.4 Find the power dissipated when: (a) a current of 5 mA flows through a resistance of 25kohm (b) a voltage of 400V is applied across a 120 kohm resistor (c) a voltage applied to a resistor i​

Answer 1

Answer:

a)

$i \: = 5 \times {10}^{ - 3}$

$r \: = 25 \times {10}^{3}$

$power = {i}^{2} \times r \\ p = 25 \times 25 \times {10}^{ - 3}$

$power \: = 0.625 \: watt$

b) v = 400 volts

r = 120*10³ ohm

$p = \frac{ {v}^{2} }{r} \\ p = \frac{16 \times {10}^{4} }{120 \times {10}^{3} }$

$p = \frac{4}{3} \: watt$

c) power = V * I

I hope this helps ... please mark me as brainliest