Q:4 (ii) A man's age is 7 times then
his son. In five years he will be four
times 95 old as his son. Find the
present age of man and son.
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Correct Question :
A man's age is 7 times then his son. In five years he will be four times as old as his son. Find the present age of man and son.
Answer:
Let the age of son be x years.
The age of the man now = 7x years
⚚ In 5 years,
- Age of son = x + 5 years
- Age of man = 7x + 5 years
☯ According to Question now,
➝ 7x + 5 = 4(x + 5)
➝ 7x + 5 = 4x + 20
Substracting 4x from both sides we get
➝ 3x + 5 = 20
Substracting 5 from both we get
➝ 3x = 15
Dividing both sides by 3 we get
➝ x = 5 years
Therefore,
- Present Age of son = x = 5 years
- Present Age of man = 7x = 7(5) = 35 years
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